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What is the print order when the following code runs?

javascript

class Meta(type):
    def __new__(mcs, name, bases, ns):
        print(f"Meta.__new__ creating {name}")
        return super().__new__(mcs, name, bases, ns)

    def __call__(cls, *args, **kwargs):
        print(f"Meta.__call__ instantiating {cls.__name__}")
        return super().__call__(*args, **kwargs)

class Foo(metaclass=Meta):
    def __init__(self):
        print("Foo.__init__")

f = Foo()

AMeta.__new__ creating Foo, Foo.__init__, Meta.__call__ instantiating Foo

BMeta.__call__ instantiating Foo, Meta.__new__ creating Foo, Foo.__init__

CMeta.__new__ creating Foo, Meta.__call__ instantiating Foo, Foo.__init__

DFoo.__init__, Meta.__new__ creating Foo, Meta.__call__ instantiating Foo

What is the output of the following code?

javascript

class NonDataDesc:
    def __get__(self, instance, owner):
        return "from descriptor"

class DataDesc:
    def __get__(self, instance, owner):
        return "from descriptor"
    def __set__(self, instance, value):
        pass

class Example:
    non_data = NonDataDesc()
    data = DataDesc()

e = Example()
e.__dict__['non_data'] = "from instance dict"
e.__dict__['data'] = "from instance dict"

print(e.non_data)
print(e.data)

Afrom instance dict, from descriptor

Bfrom descriptor, from descriptor

Cfrom descriptor, from instance dict

Dfrom instance dict, from instance dict

What is the output of the following code?

javascript

import asyncio

async def async_range(n):
    for i in range(n):
        await asyncio.sleep(0)
        yield i

async def main():
    result = [x async for x in async_range(3)]
    print(result)

asyncio.run(main())

ATypeError: 'async_range' is not iterable

B[0, 1, 2]

CSyntaxError

D[0, 1, 2, 3]

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